battle, nineteenth century
Battle of Sand Butte
Battle of Sand Butte was a battle fought on 26 April 1873 in what is now California, United States. It was part of the Modoc War, which ran from 1872 to 1873. The recorded result: Modoc victory. Recorded strength: 20–30 warriors against ~70 soldiers; ~12 Indian scouts.
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Where it sits in the Modoc War
Record
| Date | 26 April 1873 | |
|---|---|---|
| Place | California, United States 41.760N, 121.524W | |
| Kind | Battle, nineteenth century | |
| Strength | 20–30 warriors | ~70 soldiers; ~12 Indian scouts |
| Casualties and losses | None | 35 casualties |
| Commanders |
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Nearest engagements
- Second Battle of the Stronghold 1873, 7.4 km N
- First Battle of the Stronghold 1873, 17 km N
- Battle of Dry Lake 1873, 20 km E
- Battle of Lost River 1872, 26 km N
- Battle of Mud Lake 1865, 240 km SE
In the same war
- Before: Second Battle of the Stronghold 15 April 1873
- After: Battle of Dry Lake 10 May 1873
- All 5 engagements of Modoc War
Elsewhere in 1873
- Khiva campaign (1873) Uzbekistan
- Battle of Portmán Spain
- Battle of Montejurra Spain
- Battle of Alpens Spain
- Battle of Eraul Spain
Battle of Sand Butte is one of 3,507 engagements of the 19th century in the atlas and one of 1,148 in present-day United States (23 in California).
Sources
Identity, coordinates, dates and the war from Wikidata Q4872290, released under CC0. Result, belligerents, commanders, strength and casualties from the infobox of the English Wikipedia article Battle of Sand Butte, revision 1370588457, read 2026-11-14, licensed CC BY-SA 4.0; the article's text is not reproduced here. Present-day country and state from Natural Earth. Dates before 1582 follow the Julian calendar as recorded.