siege, nineteenth century
Siege of Fort Texas
Siege of Fort Texas was a siege conducted in 1846 at Fort Brown, in what is now Texas, United States. It was part of the Mexican-American War, which ran from 1846 to 1848. Recorded strength: 500 infantry men against 1,600; 14 artillery pieces.
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Where it sits in the Mexican-American War
Record
| Date | 1846 (year precision) to 9 May 1846 | |
|---|---|---|
| Place | Fort Brown, Texas, United States 25.898N, 97.492W | |
| Kind | Siege, nineteenth century | |
| Strength | 500 infantry men | 1,600; 14 artillery pieces |
| Casualties and losses | 2 killed; 10 wounded | 2 killed; 2 wounded; 3 prisoners wounded |
| Commanders |
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Nearest engagements
- Battle of Brownsville 1863, 0.6 km NW
- Battle of Matamoros 1836, 2.4 km SW
- Battle of Resaca de la Palma 1846, 4.4 km N
- Battle of Palo Alto 1846, 14 km N
- Battle of Palmito Ranch 1865, 21 km E
Contested ground: this site was fought over 4 times between 1836 and 1863.
In the same war
- Before: Battle of Monterrey 1846
- After: Battle of San Pasqual 1846
- All 41 engagements of Mexican-American War
Elsewhere in 1846
- Battle of Aliwal India
- Battle of Sobraon India
- Battle of Chino United States
- Battle of San Antonio Uruguay
- Battle of Baddowal India
Siege of Fort Texas is one of 3,507 engagements of the 19th century in the atlas and one of 1,148 in present-day United States (58 in Texas).
Sources
Identity, coordinates, dates and the war from Wikidata Q815139, released under CC0. Result, belligerents, commanders, strength and casualties from the infobox of the English Wikipedia article Siege of Fort Texas, revision 1370741253, read 2026-11-14, licensed CC BY-SA 4.0; the article's text is not reproduced here. Present-day country and state from Natural Earth. Dates before 1582 follow the Julian calendar as recorded.